9/6/21 If cot x tan x = sec x, then x is equal to A 2nπ \(\frac{3π}2\),n ∈ Z B nπ (1)n \(\ C nπ \(\frac{π}2\),n ∈ Z D None of these28/6/19 General solution of tan(2x)tan(x) = 1 For the question, tan(2x)tanx = 1, I divided it by tanx, and got the solution as ( 2n 1) π 6 tan2x = cotx = tan(π 2 − x) So, 2x = nπ π 2 − x So, 3x = ( 2n 1) π 2 But the book solved using the formula of tan(2x), and got the solution as ( 6n ± 1) π 6 I can see that my solution has oddIf cot2x =cot(x−y)cot(x −z), then cot2x is equal to (where x =±π/4 )
3 2 I Prove That Tan X Cot X Can Never Be Equal To Scholr
